The Official Radare2 Book — страница 56 из 64

|           0x08048487      83ec18         sub esp, 0x18

|           0x0804848a      8d45fc         lea eax, [var_4h]

|           0x0804848d      89442408       mov dword [var_8h], eax

|           0x08048491      c74424046886.  mov dword [var_sp_4h], 0x8048668 ; [0x8048668:4]=0x50006425 %d

|           0x08048499      8b4508         mov eax, dword [arg_8h]

|           0x0804849c      890424         mov dword [esp], eax

|           0x0804849f      e800ffffff     call sym.imp.sscanf         ; int sscanf(const char *s, const char *format,   ...)

....

The mov dword [esp], eax is the nearest instruction to sscanf (and it's equivalent to a push instruction). It stores the string 's' to the stack top (arg1). mov dword [var_sp_4h], 0x8048668 push '%d' as arg2 into stack. var_8h (esp + 0x8) which keeps the address of var_4h is the arg3.

Finally we have the corrected pseudo code:

uint32_t parell (char * s) {

sscanf (s, %d, &var_4h);

if ((var_4h & 1) == 0) {

printf ("Password OK!\n");

exit(0);

}

return 0;

}

Now there are 2 constraints:

   • Digit Sum is 16 (0x10)

   • Must be an odd number (1 & number == 0)

The password is at our fingertips now.

./crackme0x05

IOLI Crackme Level 0x05

Password: 88

Password OK!


./crackme0x05

IOLI Crackme Level 0x05

Password: 12346

Password OK!

we can also use angr to solve it since we have two constraints to the password.

IOLI 0x06

nearly a routine to check this binary (not complete output in the following):

rabin2 -z ./crackme0x06

[Strings]

nth paddr      vaddr      len size section type  string

―――――――――――――――――――――――――――――――――――――――――――――――――――――――

0   0x00000738 0x08048738 4   5    .rodata ascii LOLO

1   0x00000740 0x08048740 13  14   .rodata ascii Password OK!\n

2   0x0000074e 0x0804874e 20  21   .rodata ascii Password Incorrect!\n

3   0x00000763 0x08048763 24  25   .rodata ascii IOLI Crackme Level 0x06\n

4   0x0000077c 0x0804877c 10  11   .rodata ascii Password:


rabin2 -I ./crackme0x06

arch     x86

baddr    0x8048000

bintype  elf

bits     32

compiler GCC: (GNU) 3.4.6 (Gentoo 3.4.6-r2, ssp-3.4.6-1.0, pie-8.7.10)

crypto   false

endian   little

havecode true

lang     c

machine  Intel 80386

maxopsz  16

minopsz  1

os       linux

static   false

va       true

and analyze it then decompile main

[0x08048400]> pdd@main

/* r2dec pseudo code output */

/* ./crackme0x06 @ 0x8048607 */

#include 


int32_t main (int32_t arg_10h) {

int32_t var_78h;

int32_t var_4h;

// adjusting stack

eax = 0;

eax += 0xf;

eax += 0xf;

eax >>= 4;

eax <<= 4;


// main logic

printf ("IOLI Crackme Level 0x06\n");

printf ("Password: ");

eax = &var_78h;

scanf (0x8048787, eax);

eax = arg_10h;

eax = &var_78h;

check (eax, arg_10h);

eax = 0;

return eax;

}

main has 3 arguments argc, argv, envp, and this program is compiled with GCC, so the stack should be like this :

[esp + 0x10] - envp

[esp + 0x0c] - argv

[esp + 0x08] - argc

[esp + 0x04] - return address

enter the check() and decompile it. this function is different from 0x05 now. but they still have similar code structure.

int32_t check (char * s, int32_t arg_ch) {

char * var_dh;

uint32_t var_ch;

uint32_t var_8h;

int32_t var_4h;

char * format;

int32_t var_sp_8h;

var_8h = 0;

var_ch = 0;

do {

eax = s;

eax = strlen (eax);

if (var_ch >= eax) {

goto label_0;

}

eax = var_ch;

eax += s;

eax = *(eax);

var_dh = al;

eax = &var_4h;

eax = &var_dh;

sscanf (eax, eax, 0x804873d);

edx = var_4h;

eax = &var_8h;

*(eax) += edx;

if (var_8h == 0x10) {

eax = arg_ch;

eax = s;

parell (eax, arg_ch);

}

eax = &var_ch;

*(eax)++;

} while (1);

label_0:

printf ("Password Incorrect!\n");

return eax;

}

Correct the sscanf part and parell part, both of them were generated incorrectly:

int32_t check (char * s, void* envp)

{

var_ch = 0;

var_8h = 0;

for (var_ch = 0; var_ch < strlen(s); ++var_ch)

{

var_dh = s[var_ch];

sscanf(&var_dh, %d, &var_4h);
// read from string[var_ch], store to var_4h

var_8h += var_4h;

if(var_8h == 0x10)

parell(s, envp);

}

printf("Password Incorrect!\n");

return 0;

}

no more info, we have to reverse parell() again.

#include 


uint32_t parell (char * s, char * arg_ch) {